Hello TRNSYS-users, I have a problem with type 56. I want to calculate the g-value of a window in a simple static example. A window with a g-value of 0,33 and an area of 1 m2 (without frame) gets 360 kJ/hm2 of direct radiation (angle of incidence: 0 degrees). The room receives Qsoltr = 93,6 kJ/hm2. Thus the g-value 0,26. Why is there a difference? I have checked it with other windows and the same mistake occures. If I use the window "without pane" I get the correct value of 360 kJ/hm2 in the room. Can anybody help me? Cheers, Robert ************************************************************* Steinbeis-Transferzentrum Energie-, Gebäude- und Solartechnik TU Braunschweig - Institut für Gebäude- und Solartechnik Dipl.-Ing. Robert Himmler Mühlenpfordtstr. 23 38106 Braunschweig Tel 0531/391-3563 Fax 0531/391-8125 robert.himmler@stz-egs.de himmler@igs.bau.tu-bs.de
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